f(x+1)=x^2+4x+8

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Solution for f(x+1)=x^2+4x+8 equation:


Simplifying
f(x + 1) = x2 + 4x + 8

Reorder the terms:
f(1 + x) = x2 + 4x + 8
(1 * f + x * f) = x2 + 4x + 8
(1f + fx) = x2 + 4x + 8

Reorder the terms:
1f + fx = 8 + 4x + x2

Solving
1f + fx = 8 + 4x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-8 + 1f + fx + -4x + -1x2 = 8 + 4x + x2 + -8 + -4x + -1x2

Reorder the terms:
-8 + 1f + fx + -4x + -1x2 = 8 + -8 + 4x + -4x + x2 + -1x2

Combine like terms: 8 + -8 = 0
-8 + 1f + fx + -4x + -1x2 = 0 + 4x + -4x + x2 + -1x2
-8 + 1f + fx + -4x + -1x2 = 4x + -4x + x2 + -1x2

Combine like terms: 4x + -4x = 0
-8 + 1f + fx + -4x + -1x2 = 0 + x2 + -1x2
-8 + 1f + fx + -4x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-8 + 1f + fx + -4x + -1x2 = 0

The solution to this equation could not be determined.

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